X^2+84x-160=0

Solution for X^2+84x-160=0 equation:

X^2+84X-160=0

a = 1; b = 84; c = -160;
Δ = b2-4ac
Δ = 842-4·1·(-160)
Δ = 7696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7696}=\sqrt{16*481}=\sqrt{16}*\sqrt{481}=4\sqrt{481}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-4\sqrt{481}}{2*1}=\frac{-84-4\sqrt{481}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+4\sqrt{481}}{2*1}=\frac{-84+4\sqrt{481}}{2}
$